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Rates and real-life calculations - Mathematics IGCSE Study Notes

Rates and real-life calculations - Mathematics IGCSE Study Notes | Times Edu
IGCSEMathematics~6 min read

Overview

Have you ever wondered how much fuel your car uses per kilometre, or how many pages a printer can print in a minute? That's what 'Rates' are all about! They help us compare how one thing changes in relation to another, like speed (distance per time) or cost per item. It's super useful for making smart choices every day, like figuring out which deal is better at the supermarket. This topic isn't just about numbers on a page; it's about understanding the world around you. From cooking to travelling, rates help us measure, compare, and predict. Knowing how to work with rates means you can solve everyday problems, plan better, and even save money! We'll explore how to calculate these rates, convert between different units (like changing kilometres per hour to metres per second), and use them to solve real-life puzzles. Get ready to become a master of practical maths!

What Is This? (The Simple Version)

Imagine you're eating sweets. You eat 5 sweets in 1 minute. That's a rate! A rate tells us how much of one thing happens for every amount of another thing. It's like a special kind of comparison.

Think of it like a recipe: 2 cups of flour for every 1 cup of milk. That's a rate! Or, if your phone battery drops 10% every hour, that's a rate too. We use rates to describe how things change together. The most common rates you'll see are:

  • Speed: How far something travels in a certain amount of time (e.g., kilometres per hour, metres per second).
  • Cost per item: How much you pay for one thing (e.g., £2 per apple, $5 per litre of milk).
  • Pay rate: How much money you earn for each hour you work (e.g., £10 per hour).

The key is that rates always involve two different units (like distance and time, or money and items) and they often use the word 'per' or a slash '/' to show this relationship.

Real-World Example

Let's say you're at the supermarket, and you need to buy orange juice. There are two options:

  • Option A: A 1-litre carton for £1.50.
  • Option B: A 2-litre carton for £2.80.

Which one is the better deal? We need to find the rate of cost per litre for each option.

For Option A: Cost = £1.50 Volume = 1 litre Rate = Cost / Volume = £1.50 / 1 litre = £1.50 per litre.

For Option B: Cost = £2.80 Volume = 2 litres Rate = Cost / Volume = £2.80 / 2 litres = £1.40 per litre.

By calculating the rate (cost per litre), we can see that Option B is cheaper per litre (£1.40) than Option A (£1.50). So, Option B is the better deal! This is super handy for saving money when shopping.

How It Works (Step by Step)

Most rate problems involve finding a rate, or using a rate to find a total amount. Here's how to tackle them: 1. **Identify the two things being compared:** What are the two quantities that are changing together? (e.g., distance and time, money and items). 2. **Determine the units:** What are the...

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Key Concepts

  • Rate: A comparison of two different quantities, showing how much of one thing there is for every amount of another.
  • Speed: A rate that measures the distance travelled per unit of time (e.g., km/h, m/s).
  • Density: A rate that measures the mass of a substance per unit of volume (e.g., g/cm³).
  • Unit Cost: A rate that tells you the price of a single unit of an item (e.g., £ per kg, $ per litre).
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Exam Tips

  • Read the question carefully to identify what rate you need to calculate or use.
  • Always check the units required for the answer and convert them early if necessary.
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